What is the answer to p2+14p-38=0

Mathematics

2 answers:

zhuklara [117]3 years ago

7 0

2p+14p=38
16p = 38
p = 38/16
p = 2.375

kakasveta [241]3 years ago

6 0

Answer:

p = -7 ±√87

Step-by-step explanation:

p2+14p-38=0 would be clearer if written as p^2+14p-38=0: use " ^ " for exponentiation.

Let's "complete the square" to solve this quadratic equation:

Taking half of the coefficient of the p term, which is 14, yields 7.

Squaring this result yields 49.

Add this 49 to p^2 + 14p and also add 49 to the right side, obtaining:

p^2 + 14p + 49 - 38 = 49

Rewriting p^2 + 14p + 49 as a perfect square, we get:

(p + 7)^2 = 87

Let's now find p. Take the square root of both sides, obtaining

p + 7 = ±√87

Isolate p by subtracting 7 from both sides:

p = -7 ±√87

These are the "solutions" or "roots" or "zeros" of p^2+14p-38=0.

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Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show

djyliett [7]

Answer:

C) The third table. K= 5

$C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5$

Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

$k=\frac{y}{x}$

2)In this case, when we divide the temperature (T) by the time (h).

$k=\frac{T}{h}$

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

$A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}$