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iris [78.8K]
3 years ago
8

Samuel wants to use his earnings from Monday and Tuesday to buy some batteries

Mathematics
2 answers:
IrinaK [193]3 years ago
4 0

Answer: There are 2 batteries which he can buy with his earnings .

Step-by-step explanation:

Since we have given that

Selling price of cans at the recycling center = $0.40 per pound

Number of pounds of cans he sold on Monday = 16.2

Number of pounds of cans he sold on Tuesday = 11.8

Total earning of Samuel is given by

(16.2+11.8)\times 0.40=\$11.2

Now, cost of battery =$5.60

So, number of batteries he can buy is given by

\frac{\text{ Total earnings}}{\text{ Cost of each battery}}\\\\=\frac{11.2}{5.6}\\\\=2

So, there are 2 batteries which he can buy with his earnings .

Schach [20]3 years ago
4 0
16.2 × .40 = $6.48
11.8 × .40 = $4.72

6.48 + 4.72 = $11.20

11.20/5.60 = 2

he can buy 2 batteries

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What is the slope of the line ?
nikitadnepr [17]

Answer:

-3/4

Step-by-step explanation:

To find the slope of a line, you need to see how much it "rises" over a certain amount of "run". In other words, for a given amount of distance traveled along the x axis, how much it traveled vertically along the y axis. In this line, for every 4 units moved to the right, the line goes up by -3 units. Therefore, the slope of the line is -3/4. Hope this helps!

4 0
3 years ago
Read 2 more answers
A four-digit number N leaves a remainder of 10 when divided by 21, a remainder of 11 when divided by 23, and a remainder of 12 w
aksik [14]

Answer:

  16

Step-by-step explanation:

There may be a formal way to solve simultaneous Diophantine equations, but I don't know what it is. So, I addressed this by solving them 2 at a time.

First of all, we want to find a relation between integers p and q such that ...

  21p+10 = 23q +11

  21p -23q = 1 . . . . . . subtract 23q+10

Using the extended Euclidean algorithm or trial and error or astute observation, we find that (p, q) = (11, 10) is a solution to this equation. Then we can write p and q as ...

  • p = 23n+11
  • q = 21n+10

for some integer n.

Then our original numbers become ...

  21p+10 = 21(23n+11)+10 = 483n +241 . . . . for some integer n

For this to be a 4-digit number, we must have n such that

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Modulo 25, the number (483n+241) is ...

  8n +16

and we want that value to be 12:

  (8n +16) mod 25 = 12

  (8n +4) mod 25 = 0 . . . . . subtract 12

  4(2n+1) mod 25 = 0 . . . .  factor out 4

For this to be true, we must have 2n+1 be a multiple of 25. The only value of n that is in the required interval [2, 20] is n=12.

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When n=12, 483n+241 = 6037. The sum of digits of 6037 is 16.

3 0
3 years ago
How many
Westkost [7]

Answer:

There are no solutions

Step-by-step explanation:

4/5 ( 20x + 5 ) = 16x - 2

Distibute on the left:

( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 2

16x + 4 = 16x - 2

Subtract 16x from both sides:

4=-2

Add 2 to each side:

6=0

No solutions

8 0
3 years ago
Read 2 more answers
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Dmitry_Shevchenko [17]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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