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AnnZ [28]
2 years ago
14

Solve for x and y:5x + 14y = 1110x + 28y = 22​

Mathematics
1 answer:
Olenka [21]2 years ago
7 0

Answer:

This wouldn't work

Step-by-step explanation:

If you times the top equation by 2 to make the 5x the same as 10x all the other numbers would be the same meaning you would be able to complete the rest of the equation

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Standard deviation of 300, 785, 670, 187, 760, 724
White raven [17]
STEP 1

Mean = \frac{300+785+670+187+760+724}{6} = \frac{3426}{6}=571

STEP 2

Subtract the mean from each data value then square the answer
300-571=-271 ⇒ (-271)^{2} =73441
785-571=214 ⇒ (214)^{2}=45796
670-571=99 ⇒ (99)^{2}=9801
187-571=-384 ⇒ (-384)^{2} =147456
760-571=189 ⇒ 189^{2}=35721
724-571=153 ⇒ 153^{2} =23409

STEP 3

Add the squared answers in STEP 2 then find the mean

\frac{73441+45796+9801+147456+35721+23409}{6}= \frac{335624}{6}=55937.3

STEP 4

Square root the answer in STEP 3
\sqrt{55937.3} =236.5

Standard deviation is 236.5
 
7 0
3 years ago
HELP HELP HELP HELP ME!!!!!!!!!!!!!!!
leonid [27]

Answer:

l=\frac{A-\frac{1}{2} \pi w^2}{2w}

Step-by-step explanation:

We essentially need to solve for l; in other words, we must isolate it to one side.

First, notice that the term \frac{1}{2} \pi w^2 doesn't have any l terms in it, so we can just move this to the left side by subtracting both sides by \frac{1}{2} \pi w^2:

A - \frac{1}{2} \pi w^2 = 2lw

Now, the right side has 2lw, so we must divide both sides by 2w to isolate l:

l=\frac{A-\frac{1}{2} \pi w^2}{2w}

<em>~ an aesthetics lover</em>

4 0
2 years ago
Please help having trouble!!
umka21 [38]

And your answer will be: m=3

7 0
3 years ago
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

6 0
3 years ago
Lateral area of a prism
olchik [2.2K]
<span>     The surface area of a right prism can be calculated using the following formula: SA 5 2B 1 hP, where B is the area of the base, h is the height of the prism, and P is the perimeter of the base. The lateral area of a figure is the area of the non-base faces only.</span>
3 0
3 years ago
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