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3 years ago

13

how much fencing would be required to fence a square field with an area of 118 sq.meters and 81 sq.decimetres

2 answers:

Alika [10]3 years ago

8 0

So your looking to find the perimeter of the square. Since the area of the square is 118.81 m2, then the perimeter is 43.6 m.

lyudmila [28]3 years ago

5 0

the area of the square is 118.81 m2, so the perimeter is 43.6 m

hope this helps :)

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What number when divided by 12 gives a quotient of 16 and a remainder of 8?

valina [46]

(12 x 16) = 192 + 8 = 200

Therefore the answer is 200 which when divided by 12 gives a quotient of 16 and a remainder of 8.

3 0

3 years ago

A factory robot recently examined some bulbs, of which 2 were flawed and 18 were not. If 30 more bulbs are examined, predict how

Oksanka [162]

Answer:

3 bulbs should be flawed

Step-by-step explanation:

2+ 18 = 20

20 bulbs were examined

2/20 = 1/10 were flawed

looking at the next 30 bulbs

30 * 1/10 = 3

3 of the next 30 bulbs should be flawed

5 0

3 years ago

I need help Plz Help me thx

Lubov Fominskaja [6]

I think its the third one

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4 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

<em><u>Substitute eqn 2 in eqn 1</u></em>

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

<em><u>Solve by quadratic equation</u></em>

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

3 years ago

Help asap my last question GIVING BRAINLIST!!!!

Alex

Answer:

1) $x < 0$

2) $x > 0$

3) $x < 10$

4) $x < -\frac{31}{55}$

5) $x \geq 0$

6) $x \geq -1$

Step-by-step explanation:

1) $-3 > 2x -3$

$2x- 3 < -3$

$2x - 3 + 3 < -3 +3$

$2x < 0$

$\frac{2x}{2} < \frac{0}{2}$

$x < 0$

2) $5 > -x + 5$

$-x + 5 < 5$

$- x + 5 -5 < 5 - 5$

$-x < 0$

$\frac{-x}{-1} < \frac{0}{-1}$

$x > 0$

3) $\frac{x}{5} -2 < 0$

$5 \times (\frac{x}{5} - 2 ) \times 5 < 0$

$x - 10 < 0$

$x -10 + 10 < 0 +10$

$x < 10$

4) $-5x + 11 > 31$

$-5x \cdot 11 < 31$

$-55x < 31$

$\frac{-55x}{-55} > \frac{31}{-55}$

$x < -\frac{31}{55}$

5) $\frac{1}{2}x - 4 \geq -4$

$\frac{1}{2}x -4 +4 \geq -4 +4$

$\frac{1}{2}x \geq 0$

$\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }$

$x \geq 0$

6) $-4x + 2 \leq 6$

$-4x +2 - 2 \leq 6 -2$

$-4x < 4$

$\frac{-4x}{-4} \leq \frac{4}{-4}$

$x \geq -1$

6 0

4 years ago