Answer:
A
Step-by-step explanation:
if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is
(x-x1)(x-x2)+(y-y1)(y-y2)=0
reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

center is (2,-4)
r=√(2²+(-4)²-(-14))
=√(4+16+14)
=√(34)
eq. of circle is (x-2)²+(y+4)²=34
or
(x²-4x)+(y²+8y)=14
(x²-4x+4)+(y²+8y+16)=14+4+16
(x-2)²+(y+4)²=34
Answer:
A
Step-by-step explanation:
I am not sure though. Sorry if it is wrong :(
It’s E :) it’s up 20 characters
For this you'll want to draw out Triangle ABC and label it as the problem gives you.
Draw a similar triangle to the first one you drew and label it the exact same way as "ABC" and then match the measurement "AB" to "HJ".
Hope this helps.