Answer:
so you divide 16x÷2xy=8/y
which also same as 8y-¹
33 is composite
49 is composite
21 is composite
Answer:
d
Step-by-step explanation:
smallest slope
Answer:

Step-by-step explanation:
We have the equation of the position of the object

We need to solve the equation for the variable a

Subtract
and
on both sides of the equality


multiply by 2 on both sides of equality


Divide between
on both sides of the equation

Finally

Answer:

Step-by-step explanation:
remember: tan(theta) = opposite/adjacent