In the class of 20 students,12 are girls. Write the ratio of the number of girls to total students

Mary has 23 marbles 7/23 of the marbles are yellow and 13/23 of the marbles are blue the rest of the marbles are green how many

deff fn [24]

Answer:

The answer here is 3.

Step-by-step explanation:

Since 7 of the marbles are yellow and 13 of them are green, you would first add these numbers together to find the number of marbles that are not green. After doing this you will find that 20 of the marbles aren't green. Since there are 23 marbles, and 20 of them aren't green, you would subtract these two numbers to find that the number of green marbles is three.

8 0

3 years ago

Given f(x) 6x – 5 a) Evaluate f(5) f(5) b) Evaluate f( - 3) f(-3) =

prisoha [69]

We have the equation f(x)=6x-5 to start with
Now in order to answer the question we have to know that f(5) is the same thing as setting x=5 and solving for f(5)

(A) f(5) = 6(5) - 5 = 30 - 5 = 25
(B) f(-3) = 6(-3) - 5 = (-18) - 5 = -23

So f(5) = 25 and f(-3) = -23

8 0

3 years ago

Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t

LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

$(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)$

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

$(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)$

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6) $=\dfrac{20}{36}$

The probability distribution of this event is given as follows.

$\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|$

First, we determine the expected Value of this event.

Expected Value

$=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67$

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning $=\dfrac{20}{36}$

If the game is played 100 times

Number of times expected to win

$=\dfrac{20}{36} \times 100\\=56$ times$

Therefore, number of times expected to loose

= 100-56

=44 times

8 0

4 years ago

A team fixed a road that was 4,800 m long. After working for 30 days, there was still 1,440 m of the road left to fix. On averag

arlik [135]

The total of the road is 4800 m long. 4800-1440=3360m
We subtract what they have yet to cover from the total to get what they have covered.
So in 30 days they covered 3360 metres.
3660/30 (3660 is divided into 30 equal groups) = 122m
On average they covered 122 metres per day.

4 0

3 years ago

Find the retail price of a backpack that has a wholesale price of $25 and is marked up 40%. Multiply $25 and 40% in decimal form

mote1985 [20]

$35 is your answer, just do 25(0.40) which gives you 10 so add that to your original 25+10=35

7 0

3 years ago

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