Answer:
H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)
If H is to be considered an absolute value from t = 0
h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground
<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>
<em><u>Solution:</u></em>
<em><u>The volume of rectangular pyramid is given as:</u></em>

Given that,
<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>
<em><u></u></em>
<em><u></u></em>
<em><u>Substitute, base area = 570 and height = 1</u></em>
Then we get,

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively
<em><u>Substitute, base area = 285 and height = 2</u></em>

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively
√3√27
=√(3*27)
=√81
=9
As 9*9=81.
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RULES:
√a√b=√ab
As (√a√b)²=((√a)²(√b)²)=√a√a√b√b=ab
When:
(√a√b)²=ab
√a√b=√ab
The missing angle is 27° because a triangle equals 180° and 180-119=61 and 61-34= 27.