-0.5 0 1 -2 1.5 Where is Point D on the number line? ?
2 answers:
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Answer:
x = - 2, x = -
Step-by-step explanation:
Given
5x² + 1 = - 13x - 5 ( add 13x - 5 to both sides )
5x² + 13x + 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 5 × 6 = 30 and sum = 13
The factors are 10 and 3
Use these factors to split the x- term
5x² + 10x + 3x + 6 = 0 ( factor the first/second and third/fourth terms )
5x(x + 2) + 3(x + 2) = 0 ← factor out (x + 2) from each term
(x + 2)(5x + 3) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
5x + 3 = 0 ⇒ 5x = - 3 ⇒ x = -
Correct answer is: distance from D to AB is 6cm
Solution:-
Let us assume E is the altitude drawn from D to AB.
Given that m∠ACB=120° and ABC is isosceles which means
m∠ABC=m∠BAC =
And AC= BC
Let AC=BC=x
Then from ΔACD , cos(∠ACD) =
Since DCB is a straight line m∠ACD+m∠ACB =180
m∠ACD = 180-m∠ACB = 60
Hence
Now let us consider ΔBDE, sin(∠DBE) =
