Answer:
Please, what is your question?
Answer:
22 for num 5
Step-by-step explanation:
Solve for y by setting one equation =to X after that you can substitute the equation into the other one let's set the first one in X= FORM
X-7y=10
-2x+14y=-20
Add 7y to both sides of the first equation to let x stand alone
X=7y+10
Now you can substitute x on the second equation
-2 (7y+10)+14y=-20
Distribute
-14y-20+14y=-20
Add and simplify
Us cancel out =0
-20=-20
0=0
They are the same equations you can also divide the second equation by -2 which would make it look like this
X-7y=10
-2 (x-7y=10)
Let me know if I have answered your question
The answer to your question is 1/4
Answer:
The speed of the jet is 
Step-by-step explanation:
The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.
1. Write the general equation for the speed:

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:


Therefore the speed of the jet is 