1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scrat [10]
3 years ago
6

show the sample space of a toss of two dice as a list denote the event of a sum of 3 or 6 or 9 on the list

Mathematics
1 answer:
Ratling [72]3 years ago
4 0
The sample space is:
(1, 1); (1, 2) - sum of 3; (1, 3); (1, 4); (1, 5) - sum of 6; (1, 6);
(2, 1) - sum of 3; (2, 2); (2, 3); (2, 4) - sum of 6; (2, 5); (2, 6);
(3, 1); (3, 2); (3, 3) - sum of 6; (3, 4); (3, 5); (3, 6) - sum of 9;
(4, 1); (4, 2) - sum of 6; (4, 3); (4, 4); (4, 5) - sum of 9; (4, 6);
(5, 1) - sum of 6; (5, 2); (5, 3); (5, 4) - sum of 9; (5, 5); (5, 6);
(6, 1): (6, 2); (6, 3) - sum of 9; (6, 4); (6, 5); (6, 6)
You might be interested in
Write the equation of a line that is perpendicular to y=-x-6 and that passes through the point (-9,-4).​
gavmur [86]

Answer:

y = x + 5

Step-by-step explanation:

Perpendicular lines have opposite reciprocal slopes, so the line will have a slope of 1.

Then, plug in the slope and given point into y = mx + b to solve for b:

y = mx + b

-4 = 1(-9) + b

-4 = -9 + b

5 = b

Plug in the slope and b into y = mx + b:

y = 1x + 5

y = x + 5

So, the equation of the line is y = x + 5

5 0
3 years ago
Which figure represents the image of parallelogram LMNP after a reflection across the line y = x?
STALIN [3.7K]

Answer:

Answer: correct choice is option 3 - figure C.

Step-by-step explanation:

Using the reflection rule, you can find coordinates of image points: L'(1,3), M'(3,4), N'(3,5) and P'(1,4). As you can see, these are coordinates of vertices of the figure C

4 0
3 years ago
Read 2 more answers
Mhanifa please help with this I find it super difficult! Thanks! I will mark brainliest! Random answers will be reported !
Artyom0805 [142]

Answer:

a)

The point that is equidistant to all sides of a triangle is called the <u>incenter</u>.

The incenter is located at the intersection of bisectors of the interior angles of a triangle.

b)

The point that is equidistant to all vertices of a triangle is called the <u>circumcenter</u>.  

The circumcenter is located at the intersection of perpendicular bisectors of the sides of a triangle.

c)

<em>See the attachment</em>

The blue lines and their intersection shows the incenter.

The red lines and their intersection shows the circumcenter.

As we see the red point- the <u>circumcenter </u>is closer to vertex B.

4 0
3 years ago
Algebra find each unknown 6/12=x/2
bearhunter [10]

Answer:

x=1

Step-by-step explanation:

6/12 = x/2

Simplify the left side by dividing the top and bottom by 6

1/2 = x/2

Using cross products

2x =2

Divide by 2

2x/2 =2/2

x=1

5 0
3 years ago
Which of the following indicates that AQRS and ATUV are similar?
anyanavicka [17]
B and c are similar to eachother
8 0
2 years ago
Other questions:
  • Given that ∠A≅∠B , Gavin conjectured that ∠A and ∠B are complementary angles.
    15·2 answers
  • How do you put -6 + 9 in a number line?
    12·1 answer
  • What equal z=? I'm to confused she didn't tell us how to do it
    12·1 answer
  • Find the x-intercept of a line whose equation is 8x+2y=4.
    9·1 answer
  • Need a problem answered pls help
    9·2 answers
  • Mr. Smith but seven tickets to the puppet show and spent a total of $43. Adult tickets cost nine dollars and children six ticket
    9·1 answer
  • 2. The sample data of EU carbon dioxide emissions has a mean of 7.9 and standard deviation of 3.6. (40 points)
    14·1 answer
  • The Barker family just left the local pet store with Lucky, their new family dog. The pet store owner told the Barker family tha
    10·1 answer
  • I need help pleaseeeeeeeeee
    8·2 answers
  • Guys pls pls help I’m in a hurry and I will mark you as brainlist!
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!