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madam [21]
3 years ago
7

The equation 9 y minus 6 x = 36 is written in standard form. What is the first step when writing an equivalent equation which so

lves for x? Divide both sides of the equation by 36. Multiply both sides of the equation by 6. Add 9y to both sides of the equation. Subtract 9y from both sides of the equation.
Mathematics
1 answer:
enot [183]3 years ago
8 0

Answer:

D. Subtract 9y from both sides of the equation.

Step-by-step explanation:

A. Divide both sides of the equation by 36.

B. Multiply both sides of the equation by 6.

C. Add 9y to both sides of the equation.

D. Subtract 9y from both sides of the equation.

Given:

9y - 6x = 36

To solve for x

Step 1: subtract 9y from both sides

9y - 6x - 9y = 36 - 9y

- 6x = 36 - 9y

Step 2: Divide both sides by -6

- 6x / -6 = (36 - 9y) / - 6

x = (36 - 9y) / - 6

The answer is

x = (36 - 9y) / - 6

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The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

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The x-intercepts are at:

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2 years ago
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Step-by-step explanation:

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5 0
3 years ago
The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

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Let the five positive integers are A,B,C,D,E

The arithmetic mean :

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On multiplying both side by 5.

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On simplification  10+E =150

On subtraction both side by 10 we get

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Therefore, the Greatest possible value of one of the integer is 140.


6 0
3 years ago
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