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vazorg [7]
2 years ago
11

Relationship B has a greater rate than Relationship A. This graph represents Relationship A.

Mathematics
1 answer:
tester [92]2 years ago
4 0

Answer:

Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75

For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6

For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7

For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8

For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5

Therefore, the correct answer is option C.

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URGENTTTTTTT 20PT.
zaharov [31]
Out of the choices provided the answers would be C,D, and E
She has four choices for the first brother's towel and three choices for the second brother's towel
ABC,ABD,ABE,ACD,ACE, and ADE are the possible outcomes.
If Fiona did not choose towel A for herself, there would be more outcomes.
Hope this helps!
4 0
3 years ago
Read 2 more answers
Solve the equation sine Ф=0.6792 for 0°≤Ф≤360
Sergio [31]

Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

180 - 42.78

= 137.33 degres.

3 0
3 years ago
Determine the equation of each line with the following properties:
iris [78.8K]

Answer:

a) y =2/3 x + 7.

b) x = -1

c) y = -4/5 x - 1/5

d) y = -3/2 x + 5/2.

Step-by-step explanation:

a) Intercept form y = mx + b where m = 2/3 and  b = 7

b) y can take any value but x is always -1.

c) Slope m = (-1-3)/ (1 - -4)

= -4/5

Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:

y - y1 = m(x - x1)

y - -1 = -4/5(x - 1)

y + 1 = -4/5x + 4/5

y = -4/5 x - 1/5

d)  The slope m of the line perpendicular to this line is:

-1 / 2/3

m = -3/2.

When x = -1 , y = 4 so using the slope intercept form of a line

y = mx + b

4 = -3/2 * -1 + b  where b = the y-intercept.

4 = 3/2 + b

b = 4 - 3/2 = 5/2.

The equation is  y = -3/2 x + 5/2.

3 0
3 years ago
What is the difference between longest insect and shortest insect in centimeters
notka56 [123]
The answer is 8.5 cm
5 0
3 years ago
Mr. Thomas drove 75 miles in May. He drove 6 times as many miles in July as he did in May. He
harkovskaia [24]

Answer:

1800 miles

Step-by-step explanation:

No. of miles driven by Mr. Thomas in May = 75

It is given that miles driven in July is 6 times of miles driven by Mr. Thomas in May(75 miles).

Thus

No. of miles driven by Mr. Thomas in July = 6 * No. of miles driven by Mr. Thomas in May   = 6*75 = 450 miles.

__________________________________________________

Another condition given   that miles driven in June is 4 times of miles driven by Mr. Thomas in July(450miles as calculated above).

Thus

No. of miles driven by Mr. Thomas in June = 4 * No. of miles driven by Mr. Thomas in July   = 4* 450 miles = 1800 miles.

No. of miles driven by Mr. Thomas in June is 1800 miles.

8 0
3 years ago
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