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vazorg [7]
3 years ago
11

Relationship B has a greater rate than Relationship A. This graph represents Relationship A.

Mathematics
1 answer:
tester [92]3 years ago
4 0

Answer:

Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75

For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6

For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7

For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8

For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5

Therefore, the correct answer is option C.

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Steven has at most $100 to spend on clothes. He wants to buy a pair of jeans that cost $36 and spend the rest on t-shirts that c
NikAS [45]
100-36=64
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4 0
3 years ago
Use Euclid’s algorithm to find the greatest common factor of the following pairs of numbers:
Black_prince [1.1K]

Answer:

The GCF (12, 78) is 6 and GCF (18, 176)   is 2.

Step-by-step explanation:

Step 1:

The greatest common factor of the number is defined as the factor of two or more numbers. The acronym of Greatest common factor is GCF.

(a)

GCF (12, 78)  

The greatest common factor of the two numbers 12 and 78 is calculated by Euclid’s algorithm as follows:

78=12\times6+6

12=6\times2+0

Therefore, the greatest common factor GCF is 6.

Step 2:

(b)

GCF (18, 176)  

The greatest common factor of the two numbers 18 and 176 is calculated by Euclid’s algorithm as follows:

176=18\times9+14

18=14\times1+4

14=4\times3+2

4=2\times2+0

Therefore, the greatest common factor GCF is 2.

6 0
3 years ago
Help me please! will give brainliest!
mr_godi [17]

Answer:

what is the question?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve pls brainliest
nadezda [96]
The answer is 5 yd.

Take the side (16 yd) and subtract it with what you already know (11 yd)
3 0
3 years ago
Round 12981 to the nearest thousand
Roman55 [17]

Answer:

Step-by-step explanation:

12981 to the nearest thousand

2 is in the the thousands place

to the right of 2 is 9 and it is higher than 5

that means 2 becomes a 3 and the hundreds, tens and ones are zeros

13,000

3 0
3 years ago
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