3 years ago

What is the difference of (5 + 3i) and (2 + 9i)?

Mathematics

1 answer:

ehidna [41]3 years ago

7 0

Answer:

3+12i

Step-by-step explanation:

The difference of 5+3i and 2 + 1999 can be calculated as follows

= 5+3i - 2+9i

Collect the like terms

= 5-2+3i+9i

= 3+12i

Hence the difference of 5+3i and 2+9i is 3+12i

You might be interested in

12 is 75% of what number

Marat540 [252]

Correct answer is 16

4 0

3 years ago

Read 2 more answers

What is the derivative of y=tan(arcsin(x))?

Anuta_ua [19.1K]

Hello,

(tg(x))'=1/cos²(x)

(arcsin(x))'=1/√(1-x²)

cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²

$(tg(arcsin(x)))'= \dfrac{1}{cos(arcsin(x)))^2} * \dfrac{1}{\sqrt{1-x^2}} \\

=\dfrac{1}{1-sin(arcsin(x))^2}* \dfrac{1}{\sqrt{1-x^2}} \\

= \dfrac{1}{1-x^2} * \dfrac{1}{\sqrt{1-x^2}} \\

\boxed{= \dfrac{\sqrt{1-x^2}}{x^4-2x^2+1}}\\

$

4 0

3 years ago

3/5 of the bicycles are minivans how many of the bicycles in the parking lot of minivans

Solnce55 [7]

2/5 are minivans which is also 20 minivans

3 0

3 years ago

How do you do algebra

grin007 [14]

Its not that hard... whats the question

4 0

3 years ago