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Lena [83]
3 years ago
9

You are trying to order 14 pound of saffron, but the ordering system wants a decimal.

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

1.4 x 10

Step-by-step explanation:

By using scientific notation the decimal will be converted into 14lbs

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What is the volume of a small cone if:
Amiraneli [1.4K]

Answer:

Volume of smaller cone =301.44

Step-by-step explanation:

First let angle of cone be\alpha.

then sin(\alpha ) = 3/5       (For bigger triangle)

Same cone angle is for smaller one because they are similar.

cos(\alpha ) = 4/5

Now for smaller cone radius be R

3/5 =R/Slant height

Slant height =5/3R

Lateral surface area =\frac{1}{2}R^{2}\beta  [R = slant height]  

Given lateral surface area =60\pi =\frac{1}{2}(\frac{5R}{3} )^{2} \beta   ...................................1

2\pi R=\frac{5R}{3}\beta        ................................................2

\beta=\frac{6\pi }{5}

Put angle beta in equation 1 and find the value of R

R =6 cm

Height =\frac{4R}{3}

Thus volume =\frac{1}{3}\pi6^{2}*8

                     =301.44

4 0
3 years ago
An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What
galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\      P(A)=\frac{5}{66}=0.075757576

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

P(D_i)=\frac{1}{6} for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}

P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}

P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}

P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}

P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}

P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0

Part A:

The probability that all of the balls selected are white:

P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)

P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\      P(A)=\frac{5}{66}=0.075757576

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find P(D_3|A)

The data required is calculated above:

P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516

7 0
3 years ago
HELP PLEASE DESPERATE!!
devlian [24]

Answer:

A,B,C

Step-by-step explanation:

in these quadrilaterals, the diagonals bisect each other paralellogram, rectangle, rhombus, square

in these quadrilaterals, the diagonals are congruent rectangle, square, isosceles trapezoid

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3 years ago
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Ali must wear a totally ginormous shirt !

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3 years ago
ASAP 6(a + 25 + 3c) =
Blizzard [7]

Answer:

6a+150+18c

Step-by-step explanation:

6(a+25+3c)

6a +6 x 25 +6 x 3c

6a + 150+6 x 3c

6a +150 +18c

7 0
3 years ago
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