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4 years ago

What’s the answer to this question ?

Mathematics

1 answer:

katrin2010 [14]4 years ago

6 0

Answer:

i cant see it

Step-by-step explanation:

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6. Solve the following equation for x. Show each step.<br> 5x + 2 = 3x + 4(2x - 1)

monitta

Answer:

x=1

Step-by-step explanation:

5x + 2 = 3x + 4(2x - 1)

Distribute the 4

5x + 2 = 3x + 8x - 4

Combine like terms

5x + 2 = 11x - 4

Subtract 5x from each side

5x -5x + 2 = 11x - 5x - 4

2 = 6x-4

Add 4 to each side

2+4 = 6x-4+4

6 = 6x

Divide each side by 6

6/6 =6x/6

1= x

4 0

3 years ago

Read 2 more answers

PLEASE HELP ME PASS

Valentin [98]

(-2 ,-15)
(-1, -7)
(0,1)
(1, -7)
(2, - 15)

7 0

3 years ago

RAW= 35, Z= _, T=_, %ile __ ?

vodomira [7]

Working entirely with the information given in the question,
it's really hard to tell what 'RAW', 'Z', 'T', or '%ile' represent.

6 0

4 years ago

Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.

zysi [14]

Answer:

a) $78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

b) $78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

$n= 40$ represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

$\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

3 0

3 years ago

What is an equation in point-slope form of the line shown in the graph, using the point<br>(2, 2)?

Airida [17]

Answer:

Step-by-step explanation:

formula=y-1=m(x-1)

sorry I dont know what the m is but the equation I have is

y-2=m(x-2)

8 0

4 years ago