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ad-work [718]
3 years ago
11

Can someone tell me what 5/6 x 9/10 is and explain it please don’t just give me a answer

Mathematics
1 answer:
nadezda [96]3 years ago
8 0
How this is solved is by

Multiply 5/6 with 9/10
This multiplication involving fractions can also be rephrased as "What is 5/6 of 9/10?"

5
6
×
9
10
is
3
4
.

Steps for multiplying fractions

Simply multiply the numerators and denominators separately:
5
6
×
9
10
=
5 × 9
6 × 10
=
45
60
After reducing the fraction, the answer is
3
4
Or 3/4
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Tony buys a CD that is priced at $13.59. He has a coupon for $1.85 off. He pays with a $20 bill. Which is the best whole number
sweet-ann [11.9K]
No he would get back $4.56. Start with $20 -13.59-1.85=4.56
3 0
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Line l and Line m are parallel lines that have been rotated 180°. The resulting images are show as l' and m'. How can you descri
olga2289 [7]
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3 years ago
Read 2 more answers
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
Evaluate the expression 3a - 2ab if a= 4 and b= 6<br><br><br> please explain, thank you !
Fofino [41]

Answer: 6

Step-by-step explanation:

3 0
3 years ago
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An aircraft flew 5 hours with the wind. The return trip took 6 hours against the wind. If the speed of the plane in still air is
Yakvenalex [24]

Answer:

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

Step-by-step explanation:

Given:

Time taken with wind = 5 hour

Time taken against wind = 6 hour

Assume;

Speed of wind = s

So,

Speed of Plane with wind = (260 + s) miles per hour

Speed of Plane against wind = (260 - s) miles per hour

Distance = speed x time

So,

(260 + s)5 = (260 - s)6

1,300 + 5s = 1,560 - 6s

11s = 260

s = 23.63 miles per hour

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

5 0
3 years ago
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