Answer:
I have no clue to be honest
<span>The hypothesis is : If Robbie wants to save money to buy a car. Conclusion : he must get a part-time job.
Robbie already started the new job yesteday. So, that makes the hypothesis true.
So, the conclusion would be : Robbie will save money to buy a car/ Robbie will buy a car.</span>
Answer: 56
Step-by-step explanation: so you have 6 already and x is next to it and it says x=8 so put the eight where next to the six and since there is nothing in the middle than you multiple 6 8 idk the other number
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
