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Zinaida [17]
4 years ago
7

can anybody help me with this problem 11/6 and 3 1/3 and i need to figure out if one is greater than or less than or equal to th

e other one
Mathematics
1 answer:
Anestetic [448]4 years ago
3 0
11/6 is less than. 6 only goes into 11 once,, so it'd be 11/6
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Can somebody help me first answer gets brainiest pls help
damaskus [11]
Answer: I believe the answer is 216 Square units.

Explanation:
1. Cut the shape in half. Now you have a square and a triangular shape.

2. The square is 12 inches on all four sides. 12 • 12 = 144. 144 is the area for the square.

3. Now, the triangular shape. The bottom of the shape is 12 because we divided the total 24 in half with the square. The left side (the longer side) of the shape is also 12 because it is parallel to the square with 12 as the same measurement. The right side (the shorter side) of the shape is 6 because it's half the size of the square’s length. The length of the top of the shape is also 12 because it is half of the square’s width of 24.

4. Now that we have found the measurements of the triangular shape, we can multiply (length • width) and add. The square is 144 units (12•12=144) and the triangular shape is 72 (12•6=72). 144 + 72= 216.

I hope this helps! :)
6 0
3 years ago
- 4 -( -6) <br><br> 7 - (-4) <br><br> thank you to who ever solves it
fomenos
-4-(-6) = 2
7-(-4) = 11
5 0
3 years ago
Read 2 more answers
1. ADEA has vertices D(8,4), E(2, 6), and F(3, 1). What are the vertices of the image after a dilation with a scale factor of 5
lubasha [3.4K]

Answer:

The vertices of the image are D' (40, 20), E' (10, 30), F' (15, 5)

Step-by-step explanation:

If the point (x, y) dilated by a scale factor k using the origin as a center of dilation, then its image is (kx, ky)

Let us use this rule to solve our question

∵ The vertices of ΔDEF are D (8, 4), E (2, 6), and F (3, 1)

∵ ΔDEF dilated by a scale factor 5

∴ k = 5

∵ The origin as the center of dilation

→ That means, multiply the coordinates of every point by 5

∴ D' = (8 × 5, 4 × 5)

∴ D' = (40, 20)

∴ E' = (2 × 5, 6 × 5)

∴ E' = (10, 30)

∴ F' = (3 × 5, 1 × 5)

∴ D' = (15, 5)

∴ The vertices of the image are D' (40, 20), E' (10, 30), F' (15, 5)

3 0
3 years ago
PLEASE HELP!!!!!!!! :)
Rudiy27

Hello from MrBillDoesMath!

Answer:  Two solutions

Discussion:

Based on the graph provided the curves intersect at two point

Thank you,

MrB

6 0
3 years ago
What is the GCF of 70 and 90
mafiozo [28]
Write out the factors of 70 and 90 and see which factor is common between the two. If there is more than one, choose the greatest one.
8 0
4 years ago
Read 2 more answers
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