Answer:
50
Step-by-step explanation:
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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brainly.com/question/1397278
Answer:
Both are 72 do you need steps?
In geometry, the three undefined terms are: the point, the plane and the straight line.
Since all the given graphs represent lines,we will need to choose the straight line among them.
Straight line is a line that has no start and no end.
From the choices:
Figures a and c are rays
figure b is a line segment
figure d is a straight line
Therefore, the correct choice is: D
