Teddy has two sisters. One of them is 3 years younger than Teddy, the other one is 7 years younger than her only brother. How ol
2 answers:
Given:
Teddy has two sisters. One of them is 3 years younger than Teddy, the other one is 7 years younger than her only brother.
To find:
The age of older sister at the time when the younger sister was born.
Solution:
Let the age of Teddy be x.
One sister is 3 years younger than Teddy.
Age of one sister = x-3 years
The other one is 7 years younger than her only brother. It means other sister is 7 years younger than Teddy.
Age of other sister = x-7 years
Clearly (x-3) > (x-7). So, difference between the ages of sisters is
Therefore, the age of older sister is 4 years when the younger sister was born.
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Answer:
Step 1: Distribute to
and
Step 2: Subtract from both sides of the equation
Step 3: Add to both sides of the equation
Step 4: Divide both sides of the equation by
Step-by-step explanation:
Step 1: Apply the Distributive Property. Then you must distribute to
and
Then:
Step 2: You must apply the Subtraction property of Equality and subtract from both sides of the equation. Then:
Step 3: You must apply the Addition property of Equality and add to both sides of the equation. Then:
Step 4: You must apply the Division property of Equality and divide both sides by . Then: