Teddy has two sisters. One of them is 3 years younger than Teddy, the other one is 7 years younger than her only brother. How ol
2 answers:
Given:
Teddy has two sisters. One of them is 3 years younger than Teddy, the other one is 7 years younger than her only brother.
To find:
The age of older sister at the time when the younger sister was born.
Solution:
Let the age of Teddy be x.
One sister is 3 years younger than Teddy.
Age of one sister = x-3 years
The other one is 7 years younger than her only brother. It means other sister is 7 years younger than Teddy.
Age of other sister = x-7 years
Clearly (x-3) > (x-7). So, difference between the ages of sisters is
Therefore, the age of older sister is 4 years when the younger sister was born.
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Answer:
f=11
Mode=4
Median=4
Explanation:
We are given that
a.Mean of the exam score,=3.5
Score(x) frequency C.F
1 1 1
2 3 4
3 f 15(4+f=4+11)
4 13 28
5 4 32
Using the formula
b.Mode:The number which is repeat most times .
4 repeat most times
Hence, mode of all exam scores=4
N=32
N is even
Median=