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rusak2 [61]
3 years ago
10

There are 7 women and 9 men if 2 are promoted what is the probability they are both men

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

3/10

Step-by-step explanation:

Total number of employees = 7 + 9 = 16

Probability of a man being chosen first to be promoted = 9/16

Probability of the second choice is still a man for promotion = 8/15

Why 8/15?

The number of men left who are eligible for promotion after the 1st man was chosen for promotion is 9 - 1 = 8

The total number of people left after the 1st person is chosen for promotion that are eligible for promotion is 16 - 1 = 15

Hence Probability of choosing 2 men for promotion = 9/16 x 8/15 = 3/10

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Math help!!!!! thanks!!!!!!!
astraxan [27]
PEMDAS
We start with exponents.
4 x 4 is 16
12 divided by 3 is 4
4 times 5 is 20
20-16 is 4
4 is the answer.
5 0
3 years ago
Read 2 more answers
Find the coordinates of the circumcenter of the triangle with the given vertices. X(-2, 1), Y(2, -3), Z(6, -3).
lana [24]

Answer:

C (4,3)

Step-by-step explanation:

Steps to find the circumcenter:

1) Find and Calculate the midpoint of given coordinates or midpoints.

2) Calculate the slope of the perpendicular bisector lines

3) By using the midpoint and the slope, find out the equation of the line

( y-y_1 )= m(x-x_1)

4) Do the same for another line

Solve the equations of two lines to get the intersection point.

The intersection point will be the circumcenter of the triangle.

Given :

X(-2,1), Y(2,-3), Z(6,-3)

Please see the attached file:

5 0
2 years ago
Evaluate x+y when x=−45 and y=13. Write your answer as a fraction or mixed number in simplest form.
cricket20 [7]

the answer is -32

you add -45 and 13

6 0
3 years ago
If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?​
Oduvanchick [21]

\large\underline{\sf{Solution-}}

<u>Given:</u>

\rm \longmapsto x = a \sin \alpha  \cos \beta

\rm \longmapsto y = b \sin \alpha  \sin \beta

\rm \longmapsto z = c\cos \alpha

Therefore:

\rm \longmapsto \dfrac{x}{a}  = \sin \alpha  \cos \beta

\rm \longmapsto \dfrac{y}{b}  = \sin \alpha  \sin \beta

\rm \longmapsto \dfrac{z}{c} = \cos \alpha

Now:

\rm =  \dfrac{ {x}^{2} }{ {a}^{2}} +  \dfrac{ {y}^{2} }{ {b}^{2} } +  \dfrac{ {z}^{2} }{ {c}^{2} }

\rm =  { \sin}^{2} \alpha  \cos^{2}  \beta   +  { \sin}^{2} \alpha  \sin^{2} \beta  +  { \cos}^{2} \alpha

\rm =  { \sin}^{2} \alpha  (\cos^{2}  \beta   +  \sin^{2} \beta  )+  { \cos}^{2} \alpha

\rm =  { \sin}^{2} \alpha \cdot1+  { \cos}^{2} \alpha

\rm =  { \sin}^{2} \alpha + { \cos}^{2} \alpha

\rm = 1

<u>Therefore:</u>

\rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} +  \dfrac{ {y}^{2} }{ {b}^{2} } +  \dfrac{ {z}^{2} }{ {c}^{2} }  = 1

5 0
2 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
Bad White [126]

Answer:

The final answers are x = 1 OR x = -3.

Step-by-step explanation:

Given the equation is x^2 -3 = -2x

Rewriting it in quadratic form as:- x^2 +2x -3 = 0.

a = 1, b = 2, c = -3.

Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)

x = ( -2 ± √(4 -4*1*-3) ) / (2*1)

x = ( -2 ± √(4 +12) ) / (2)

x = ( -2 ± √(16) ) / (2)

x = ( -2 ± 4 ) / (2)

x = (-2+4) / (2) OR x = (-2-4) / (2)

x = 2/2 OR x = -6/2

x = 1 OR x = -3

Hence, final answers are x = 1 OR x = -3.

8 0
2 years ago
Read 2 more answers
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