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Arada [10]
3 years ago
8

4m-5t=-22 5m+6t=-3 Solve by Elimination

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0
4m-5t=-22\\
5m+6t=-3\\\\
-20m+25t=110\\
20m+24t=-12\\
---------\\
49t=98\\
t=2\\\\
4m-5\cdot2=-22\\
4m-10=-22\\
4m=-12\\
m=-3
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HELP PLEASE!!! EASY I just haven't done algebra in a while so I forgot lol.
ElenaW [278]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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Bob makes 4% commission on his sales as a real estate agent. If Bob sells a house for $249,000, how much money does he get to ke
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He gets to keep $9,960 of the sale
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Which term could be put in the blank to create a fully simplified polynomial written in standard form?
Katena32 [7]

Correct Question:

Which term could be put in the blank to create a fully simplified polynomial written in standard form?

8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3

Options

x^2y^2            x^3y^3         7xy^2         7x^0y^3

Answer:

x^2y^2

Step-by-step explanation:

Given

8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3

Required

Fill in the missing gap

We have that:

8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3

From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.

Hence, the variable of the polynomial is x

This implies that the power of x decreases by 1 in each term.

The  missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.

This implies that the blank will be filled with a term that has its power of x to be 2

From the list of given options, only x^2y^2 can be used to complete the polynomial.

Hence, the complete polynomial is:

8x^3y^2 -x^2y^2+ 3xy^2 - 4y3

4 0
3 years ago
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Write each decimal as a fraction or mixed number in simplest form.<br> 1 3/8
Mnenie [13.5K]

3/2

<em>Step One:</em> 1 3/8, transform the number into a improper fraction:

  1. To have a mixed number in to a improper fraction, you need to use            addition and multiplication.  For 1 3/8, We first multiply the denominator (8, also know to be the bottom number of the fraction) to the whole number (1).  8x1= 8
  2. NOTE: The original denominator (8) will be use for are improper, again playing as the denominator, we only multiply the denominator for the numerator (which is the top number of a fraction).
  3. After multiplying, we'll add are product with the numerator (3) for the process. 8+3= 12
  4. Now we have both numerator and denominator for 1 3/8, we can create the improper fraction. 12 as the numerator and 8 as the denominator. 12/8
  5. We still need to simplify the number. To that, we need the biggest whole number, or rather I call it the lowest number, that can be divide both in 12 and 8.
  6. 4 can be divide by both number so: 12/4= 3 and 8/4=2
  7. Now 3 is are simplify numerator and 2 is are simplify denominator.

8 0
3 years ago
Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the d
jolli1 [7]

Answer:

Segment EH and segment E prime H prime both pass through the center of dilation (A)

The complete question related to this found on brainly (ID:16812154) is stated below:

Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the dilation?

E(0,5) F(1,1) G(-2,1) H(0,1)

a) segment EH and segment E prime H prime both pass through the center of dilation.

b)The slope of segment EF is the same as the slope of segment E prime H prime.

c) segment E prime G prime will overlap segment EG. segment

d) EH ≅ segment E prime H prime.

Step-by-step explanation:

∆EFG = Original image

∆EFG is dilated to give ∆E'F'G'

∆E'F'G' = New image

Scale factor = 3

Center of dilation = (0,1) = H(0,1)

Coordinates ∆EFG : E(0,5) F(1,1) G(-2,1)

To determine the statement that is true about the dilation from the options,

First we would make a diagram on the coordinates of ∆EFG and center of dilation (H).

Find attached the diagram.

Length GF = 3unit

Length G'F' = 3×scale factor = 9unit

Length EH = 4unit

Length E'H' = 4×scale factor = 12unit

Then we would move 3units to the left on same line from G to get the coordinate of G'(mark the point).

Also move 3units to the right on same line from F to get the coordinate of F'(mark the point).

Both of these give length of G'F' = 9unit

Now move 8units to the top from E to get the coordinate of E'(mark the point).

From this you get length E'H' = 12unit

Draw lines connecting the three points to get ∆E'F'G'

See diagram for better understanding

From the diagram, EH and E'H' both pass through (0,1). The other options are wrong.

Therefore, Segment EH and segment E prime H prime both pass through the center of dilation (A)

5 0
3 years ago
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