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Arada [10]
3 years ago
8

4m-5t=-22 5m+6t=-3 Solve by Elimination

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0
4m-5t=-22\\
5m+6t=-3\\\\
-20m+25t=110\\
20m+24t=-12\\
---------\\
49t=98\\
t=2\\\\
4m-5\cdot2=-22\\
4m-10=-22\\
4m=-12\\
m=-3
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choli [55]
Let x = no. of 10 oz cups sold
Let y = no. of 14 oz cups sold
Let z = no. of 20 oz cups sold
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Equation 1: total number of cups sold:
x + y + z = 24
:
Equation 2: amt of coffee consumed:
10x + 14y + 20z = 384
:
Equation 3: total revenue from cups sold
.95x + 1.15y + 1.50z = 30.60
:
Mult the 1st equation by 20 and subtract the 2nd equation from it:
20x + 20y + 20z = 480
10x + 14y + 20z = 384
------------------------ subtracting eliminates z
10x + 6y = 96; (eq 4)

Mult the 1st equation by 1.5 and subtract the 3rd equation from it:
1.5x + 1.5y + 1.5z = 36.00
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---------------------------subtracting eliminates z again
.55x + .35y = 5.40; (eq 5)

Multiply eq 4 by .055 and subtract from eq 5:
.55x + .35y = 5.40
.55x + .33y = 5.28
--------------------eliminates x
0x + .02y = .12
y = .12/.02
y = 6 ea 14 oz cups sold 

Substitute 6 for y for in eq 4
10x + 6(6) = 96
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x = 60/10
x = 6 ea 10 oz cups

That would leave 12 ea 20 oz cups (24 - 6 - 6 = 12)

Check our solutions in eq 2:
10(6) + 14(6) + 20(12) =
60 + 84 + 240 = 384 oz

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