-2(x + 3) = -2(x + 1) - 4
-2x - 6 = -2x - 2 - 4
0x = -6 + 6
0x = 0
x = unknown
5.3 minutes.
First, let's calculate the volume of the tank. That will be the area of the base multiplied by it's length. And since it's base is a circle, the area is pi*r^2. So:
V = l*pi*r^2
V = 3.5 * pi * (2.2/2)^2
V = 3.5 * pi * (1.1)^2
V = 3.5 * pi * 1.21
V = 4.235 * pi
V = 13.30464489
So the tank has a volume of about 13.3 ft^3. Now simply divide that volume
by the rate of incoming fluid. So
13.3 / 2.5 = 5.32
Rounding to 2 significant figures gives a time of 5.3 minutes.
Answer:
0
Step-by-step explanation:
slope = dy/dx
= 0/x
= 0
Answer:
See attachment
Step-by-step explanation:
On attachment
Complete Question:
A population proportion is 0.4. A sample of size 200 will be taken and the sample proportion p will be used to estimate the population proportion. Use z- table Round your answers to four decimal places. Do not round intermediate calculations. a. What is the probability that the sample proportion will be within ±0.03 of the population proportion? b. What is the probability that the sample proportion will be within ±0.08 of the population proportion?
Answer:
A) 0.61351
Step-by-step explanation:
Sample proportion = 0.4
Sample population = 200
A.) proprobaility that sample proportion 'p' is within ±0.03 of population proportion
Statistically:
P(0.4-0.03<p<0.4+0.03)
P[((0.4-0.03)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.03)-0.4)/√((0.4)(.6))/200
P[-0.03/0.0346410 < z < 0.03/0.0346410
P(−0.866025 < z < 0.866025)
P(z < - 0.8660) - P(z < 0.8660)
0.80675 - 0.19325
= 0.61351
B) proprobaility that sample proportion 'p' is within ±0.08 of population proportion
Statistically:
P(0.4-0.08<p<0.4+0.08)
P[((0.4-0.08)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.08)-0.4)/√((0.4)(.6))/200
P[-0.08/0.0346410 < z < 0.08/0.0346410
P(−2.3094 < z < 2.3094)
P(z < -2.3094 ) - P(z < 2.3094)
0.98954 - 0.010461
= 0.97908
