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2 years ago

What is length of BC ?

Mathematics

1 answer:

MAXImum [283]2 years ago

5 0

Answer:

BC = 10

Step-by-step explanation:

Since this is an isosceles triangle

AC = BC

3x-5 = 2x

Subtract 3x from each side

3x-5-3x = 2x-3x

-5 = -x

Multiply each side by -1

5 =x

BC = 2x

=2 *5

BC =10

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Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.

kolezko [41]

Answer:

$A=4.5u^2$

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

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$\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2$

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3 years ago

Find the value of f(5) for the function.<br><br> F(x)=6+3x

GuDViN [60]

Answer:

Explanation:

To solve this problem, you substitute in the 5 for the x creating this equation: f(5)=6+3(5).

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2 years ago

Pls help question on the photo 30000000 points

trasher [3.6K]

Answer:

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Step-by-step explanation:

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so (10)+(2x+2)+(2x-3)

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3 years ago