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Delicious77 [7]
2 years ago
12

Can anyone help me with this please?

Mathematics
2 answers:
lozanna [386]2 years ago
8 0
Equal, greater than, less than in that order
Kisachek [45]2 years ago
7 0

Answer:

1. =

2. Greater than (wide part facing left)

3. Greater than (wide part facing left)

Step-by-step explanation:

1. The numbers are the same, even though one has more zeros on the right.

2. Make the 0.03 a fraction. 3/100. Then add it to 6/10 which changes to 60/100. Those added up are 63/100. Do the same for the other one and you get 36/100. 63/100 is greater.

3. Pretend that the 9 has a 0 on the end of it. That becomes 90%. However, since the 12 is already in the hundredths place, it is only 12% making 0.9 larger.

You might be interested in
Complementary angles mean all 3 angles equal how many degrees?​
Montano1993 [528]

Answer:

Two Angles are Complementary when they add up to 90 degrees (a Right Angle)

Step-by-step explanation:

Please mark Brainliest :)

3 0
2 years ago
What is the answer to 85% of 62
Stella [2.4K]

Answer:

52.7

Step-by-step explanation:

Of means multiply

85% * 62

.85 * 62

52.7

6 0
2 years ago
Read 2 more answers
Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
(07.05)<br> Graph the first six terms of a sequence where a = -10 and d = 3.
butalik [34]

Answer:

15

Step-by-step explanation:

Using the formular, Sn = n/2(2a + (n - 1)d)

where, n = 6: Sn = 6/2( -20 + 5(3)) = 3(15 - 20)

∴  Sn = 15

7 0
3 years ago
Solve each system using SUBSTITUTION. Remember to check!
Annette [7]

Answer:

\left \{ {{x=3} \atop {y=-7}} \right.

Step-by-step explanation:

We can directly substitute y of the first equation to the second equation.

-2x - 1 = 3x - 16

5x = 15

x = 3

Substituting back to any of the two equations, we get y = -2(3)-1 = -7.  If you check with the second equation, y = 3(3)-16 = -7 as well.

Therefore \left \{ {{x=3} \atop {y=-7}} \right..

7 0
2 years ago
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