Okay so you have to add up 15 and 11 and 4 so your answer is y=30
The missing side would be 10
Answer:
22
Step-by-step explanation:
Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j
Pretend the addition 5 values is k,l,m,n,o
So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20
So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300
Now let's look at the first 10: We have their mean so we can write:
(a+b+c+d+e+f+g+h+i+j)/10=19
so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190
So that means using our first sum equation and our equation sum equation we have
190+k+l+m+n+o=300
k+l+m+n+o=300-190
k+l+m+n+o= 110
So the average of those 5 numbers mentioned in your problem is 110/5=22
Using the law of cosines:
The grocery store to the school:
Distance = √(7^2 + 10^2 - 2*7*10*cos(100)
Distance = 13.16 miles
The movie store to the school:
Distance = √(7^2 + 10^2 - 2*7*10*cos(120)
Distance = 14.80 miles
The friend is further away.
