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2 years ago

6

The radius of a sphere = 5ft. Calculate the ENTIRE volume of the sphere

1 answer:

yKpoI14uk [10]2 years ago

8 0

Answer:

V≈523.6ft³

Step-by-step explanation:

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Find the equation of the line that passes through the point (1,2) with a slope of 4. Plug in your values for a and b into the eq

ryzh [129]

Answer:

y=4x-2

you can find the y intercept if you plot a confirmed point on a graph and follow the slope to the line.

8 0

3 years ago

Read 2 more answers

The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviat

Harlamova29_29 [7]

Answer:

The bolts with diameter less than 5.57 millimeters and with diameter greater than 5.85 millimeters should be rejected.

Step-by-step explanation:

We have been given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviation of 0.08 millimeters.

Let us find the sample score that corresponds to z-score of bottom 4%.

From normal distribution table we got z-score corresponding to bottom 4% is -1.75 and z-score corresponding to top 4% or data above 96% is 1.75.

Upon substituting these values in z-score formula we will get our sample scores (x) as:

$z=\frac{x-\mu}{\sigma}$

$-1.75=\frac{x-5.71}{0.08}$

$-1.75*0.08=x-5.71$

$-0.14=x-5.71$

$-0.14+5.71=x-5.71+5.71$

$5.57=x$

Therefore, the bolts with diameters less than 5.57 millimeters should be rejected.

Now let us find sample score corresponding to z-score of 1.75 as upper limit.

$1.75=\frac{x-5.71}{0.08}$

$1.75*0.08=x-5.71$

$0.14=x-5.71$

$0.14+5.71=x-5.71+5.71$

$5.85=x$

Therefore, the bolts with diameters greater than 5.85 millimeters should be rejected.

7 0

2 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago

This is the question

zysi [14]

Answer:(1,1)

Step-by-step explanation:

Its asking where both linear and curve lines are being hit,

(fxg)(0)= 1,1

3 0

2 years ago

1 gallon of milk divided into 10 glasses

Anon25 [30]

I believe that’s 16 cups. I could be wrong but probably right lol

3 0

2 years ago