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Verizon [17]
3 years ago
9

Find the value of X in the figure PQ is tangent to O at P

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:13

Step-by-step explanation:

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Solve st + 3t = 6 for s
vaieri [72.5K]

st + 3t = 6 for s

Subtract 3t to both sides

st + 3t  - 3t = 6 - 3t

Simplify

st = 6 - 3t

Divide both sides by t

st/t = (6-3t)/3

simplify

s = 6/3 - 3t/3

s = 2 - t


6 0
3 years ago
What is the solution set for -4 x - 10 ≤ 2?<br> A. x ≤ -3<br> B. x ≥ -3<br> C.x ≤ -3<br> D. x ≥ 2
kramer

Answer:

B. x ≥ -3

Step-by-step explanation:

-4 x - 10 ≤ 2

add ten by both sides

-4x≤12

divide -4 by both sides

x ≤ -3

BUT because you divded  you have to switch the sign so

x ≥ -3

6 0
2 years ago
Read 2 more answers
Definition: The statement formed when an equal sign is placed between two expressions is called an
melamori03 [73]

Answer:

equation

example=2+3=5

7 0
3 years ago
reasoning: if you know that 9 x 20 = 180, how can you use this to find 9 x 24? explain your strategy.
Lostsunrise [7]
9 * 20 = 180

24 has 4 more than that, so multiply 9 to 4 and add it to 180.

9 * 4 = 36

180 + 36 = 216

So 9 * 24 = 216
4 0
3 years ago
Read 2 more answers
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
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