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Anuta_ua [19.1K]
3 years ago
10

What is the answer to... 5m+8n-2(3m-n)?

Mathematics
2 answers:
Paladinen [302]3 years ago
5 0
-m +10 is the correct answer
Korolek [52]3 years ago
4 0

Answer:

-m + 10n

Step-by-step explanation:

5m+8n-6m+2n = -m+10n

You might be interested in
Answer this question if cool
maxonik [38]

Answer:

The answer to your question is given below

Step-by-step explanation:

From the question given above, the mean score is 23.

Thus, we can obtain the distance from the mean (absolute deviation) by using the following formula:

Mean deviation = | mean – Score |

Mean = 23

For Score 21:

Mean deviation = | mean – Score |

Mean deviation = | 23 – 21 | = 2

For Score 22:

Mean deviation = | mean – Score |

Mean deviation = | 23 – 22 | = 1

For Score 28:

Mean deviation = | mean – Score |

Mean deviation = | 23 – 28 | = 5

For Score 29:

Mean deviation = | mean – Score |

Mean deviation = | 23 – 29 | = 6

SUMMARY:

Score >> Mean >> Absolute deviation

21 >>>>> 23 >>>>> 2

21 >>>>> 23 >>>>> 2

21 >>>>> 23 >>>>> 2

22 >>>>> 23 >>>>> 1

22 >>>>> 23 >>>>> 1

22 >>>>> 23 >>>>> 1

22 >>>>> 23 >>>>> 1

22 >>>>> 23 >>>>> 1

28 >>>>> 23 >>>>> 5

29 >>>>> 23 >>>>> 6

7 0
3 years ago
What’s 18/1 as a mixed number
Alina [70]

Answer:

18

Step-by-step explanation:

18 over 1 is still 18. It shouldn't be a mixed number

3 0
3 years ago
Read 2 more answers
Kayle and Olivia both just got their first jobs. After working for two weeks they received pay checks. Kayle received her check
MaRussiya [10]

Answer:

ovlivia makes more per hour than kayle

Step-by-step explanation:

ovlivia makes $8.75 per hour while Kayle makes $8.5 per hour

6 0
3 years ago
Solve the problem down below:<br><br><br><br> ty :P
AVprozaik [17]

Answer:

the correct answer is1/4

5 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
4 years ago
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