<span>Say the code only needed to be one number long. Going from 0-9, there are ten digits. Therefore, there are ten unique codes.
Now say the code has to be two numbers long. There are ten possibilities
for the first digit, 0-9. But the second digit only has nine
possibilities, since each number has to be different. (The first number
might be 0, so the second can only go from 1-9) For each of the first
ten possibilities, there are nine possibilities for the second. We
multiply those two numbers together, 10 * 9, and we get 90.
Now we just extend the logic. The third number only has eight
possibilities, while the fourth number only has seven. 10 * 9 * 8 * 7 =
5040 possible codes. I hope this helped! has a great day! :)</span>
Answer:
4
Step-by-step explanation:
Answer:
13 square units
Step-by-step explanation:
You <em>could</em> calculate the length of each side using Pythagorean theorem, then use Heron's formula to find the area. But there's an easier way: find the area of the rectangle that contains the triangle, and subtract the areas of the smaller triangles in the corners.
The area of the rectangle is 4 × 7 = 28.
The area of the upper left triangle is ½(2)(4) = 4.
The area of the upper right triangle is ½(3)(5) = 7.5.
The area of the lower right triangle is ½(1)(7) = 3.5.
So the area of the triangle is:
28 − 4 − 7.5 − 3.5 = 13
Answer:
hckkcjl4yhjvgvccbjjhjc,zbhbbmk jlkvcuko
The answer is sometimes. Hope that helped!
