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sergij07 [2.7K]
2 years ago
7

Given f(x) = 3x − 4 and g(x) = f(2x), which table represents g(x)?

Mathematics
1 answer:
love history [14]2 years ago
4 0

Answer:

answer is d

Step-by-step explanation:

from question

g(x) = 2(3x) - 4 = 6x - 4

then put x = 1,2,3

so g(x) = 2,8,14

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HELPPP....PLEASE...........
kogti [31]

Answer:

9 1/3, 12 1/2, 14 3/4

Step-by-step explanation:

I assume the formula you’re working with is A=b*h since nothing says otherwise...

((Patio 1))

So you have your area (147) and your base (15 3/4), now you need to plug them in, which should look like this:

147= 15 3/4*h

You need to isolate your h in order to get the missing number, so you should divide both sides by 15 3/4 OR 63/4 ((15*3—>60+3=63))

Dividing by a fraction is the equivalent of multiplying by its reciprocal... so

147 * 4/63 = 588/63 which can be simplified to 84/9 once both the numerator and denominator are divided by 7

In mixed number for it is 9 3/9 which simplified becomes 9 1/3

You solve the other similarly

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3 years ago
Math question (working too, if possible)
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4/15 of the Primary School chose chicken nuggets.
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PLEASE ANSWER THIS MATH QUESTION !! THANK U !! 19 POINTS AND BRAINLIEST !!
Karolina [17]

Answer:

a

Step-by-step explanation:

the side x looks smaller than 8 m.

The only option smaller than 8 m is a, 5.2 m

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3 years ago
Which expression is equivalent to the given expression. pls help :)
Tomtit [17]

Answer:

B

Step-by-step explanation:

\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\\(a^{m})^{n} =a^{mn}

\frac{(4m^{2}n)^{2}}{2m^{5}n}=\frac{4^{2}(m^{2})^{2}n^{2}}{2m^{5}n}\\\\\\=\frac{16m^{4}n^{2}}{2m^{5}n}\\\\\\=\frac{8m^{4}n^{2}}{2m^{5}n}\\\\\\=8m^{(4-5)}n^{(2-1)}\\\\\\=8m^{-1}n

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Title:

<h2>Check the explanation.</h2>

Step-by-step explanation:

As all the questions of the exam carry 2 points, at least \frac{56}{2} = 28 questions need to be correct to get 56 marks.

In order to get a maximum of 56 marks, at most 28 answers needs to be correct.

Every question has two option. Hence, the probability of getting a particular question right is \frac{1}{2}.

The probability that exactly n questions will be right is ^{50}C_n (\frac{1}{2} )^n (\frac{1}{2} )^{50 - n} = ^{50}C_n (\frac{1}{2} )^{50}.

The probability that at most 28 questions will be right is ∑^{50}C_n (\frac{1}{2} )^{50}, 0\leq n\leq 28.

Similarly, the probability that at least 30 questions will be right is ∑^{50}C_n (\frac{1}{2} )^{50}, 30\leq n \leq 50.

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