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Darina [25.2K]
4 years ago
8

What are algebra problems nurses use

Mathematics
1 answer:
Paha777 [63]4 years ago
5 0

Answer:linear equations

Step-by-step explanation:

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Select the correct answer from the each drop-down menu. if 0
diamong [38]

Answer:

You didn't provide a image of the problem how am I suppose to help you

8 0
3 years ago
Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465
disa [49]

<u>Answer:</u>

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is 3^{(x+2)}=15

We have to solve the above expression using change of base formula which is given as

\log _{b} a=\frac{\log a}{\log b}

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, x+2=\log _{3} 15

By using change of base formula,

x+2=\frac{\log _{10} 15}{\log _{10} 3}

x + 2 = 2.4649

x = 2.4649 – 2  = 0.4649

Hence, the value of x is 0.465 approximately and second option is correct one.

3 0
3 years ago
Read 2 more answers
4/25 of the purchases were stuffed animals. 10/21 of them were bears. What fraction of the purchases were stuffed bears?
Bess [88]
Let's name all the purchases "x"

so \frac{4}{25}of them were stuffed animals, and out of that \frac{10}{21} were bears.

to get the results we have to multiply the fraction of bears by the fraction of the stuff animals:

\frac{4}{25}*\frac{10}{21}.
 
and now we simplify:
\frac{4*2}{5*21}=\frac{8}{105}

and this is the answer!






4 0
3 years ago
The area of a triangle is one-half times the base times the height. If the area of a
dsp73

Answer:

The base is 90 sq

Step-by-step explanation:

Formula for Area= 1/2*b*h

where b is unknown and area = 54sq

<h2>Placing in formula</h2>

1/2 *b*12 = 54sq

12b = 54*2

12b /12 = 54*2/12

b = 9sq

5 0
3 years ago
Yo if you can help me I'll give brainliest.
Luden [163]

Answer: x = 5; y = -5

\left \{ {{-7x-3y=-20} \atop {3x+6y=-15}} \right. \\\\\left \{ {{-7x-3y=-20} \atop {x+2y=-5}} \right. \\\\\left \{ {{-7(-5-2y)-3y=-20} \atop {x=-5-2y}} \right. \\\\\left \{ {{35+14y-3y=-20} \atop {x=-5-2y}} \right. \\\\\left \{ {{11y=-55} \atop {x=-5-2y}} \right. \\\\\left \{ {{y=-5} \atop {x=5}} \right.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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