The correct factorization is
2(x-2)²
Answer:
a 10 yd 2ft 7 in
b 10 yd 1 ft 2 in
c 99 yd
d. 4840 sq yd 7 sq ft 119 sq in
Step-by-step explanation:
a. 2 ft. 5 in. +
9 yd. 3 ft. 2 in.
---------------------
9 yd 5ft 7 in
but 3 ft = 1yd
9 yd 5ft 7 in
+1yd - 3ft
---------------------------
10 yd 2ft 7 in
b. 4 yd. 8 in
+ 6 yd. 6 in.
----------------------
10 yd 14 in
but 12 in = 1ft
10 yd 14 in
+ 1ft - 12 in
---------------------
10 yd 1 ft 2 in
c. 29 yd. 2 ft. 11 in.
55 yd. 1 ft. 10 in.
+ 13 yd. 1 ft. 3 in.
--------------------------
97 yd 4 ft 24 in
12 in = 1ft
24 in = 2ft
97 yd 4 ft 24 in
+2ft - 24 in
--------------------------------
97 yd 6ft
3 ft = 1yd
6f = 2yd
97 yd 6ft
+2yd - 6ft
---------------------
99 yd
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.
+ 7 sq. ft. 124 sq. in.
--------------------------------------------------
4839 sq yd 15 sq ft 263 sq in
12*12 = 144 sq in = 1 sq ft
4839 sq yd 15 sq ft 263 sq in
+ 1 sq ft - 144 sq in
--------------------------------------------------
4839 sq yd 16 sq ft 119 sq in
3ft * 3 ft = 9 sq ft = 1 sq yd
4839 sq yd 16 sq ft 119 sq in
+1 sq yd - 9 sq ft
----------------------------------------------
4840 sq yd 7 sq ft 119 sq in
X , y = 0
0 = 2x - 10
2x = 10
x = 5
Answer:
5 friends
Step-by-step explanation:
Candy pieces = 60
Chocolate = 45
What should be the smallest number of her sister's friends for the distribution of candy and chocolate so each friend gets an equal number of candy pieces and chocolates in a way that there should not be left any chocolate or candy pieces left over?
To calculate this, find the lowest factor of 60 and 45
60:
Factors = 2, 4, 5, 6,
45:
Factors= 3, 5, 9
The lowest common factor of 60 and 45 is 5
The smallest number of her sister's friend so each person get an equal number of candy pieces and chocolate so there won't be any leftover is 5
That is
If there are 5 friends at the birthday party
60 candy pieces among 5 friends
= 60/5
= 12 pieces each
45 chocolate among 5 friends
= 45/5
= 9 each
Answer:
since the sum of interior angles of hexagon is 720 °
you add the known angles
ie 115 +90+145+160
you get 510
subtract it from 720
you get 210
divide 210 by 3
you get 70
angle cde is 140
