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Basile [38]
3 years ago
12

Jellybeans cost $0.80 per pound. Howard buys 412 pounds of jellybeans for himself and 1 pound for his friend. What is the total

cost of the jellybeans Howard buys?
(A.) $4.00

(B.) $4.40

(C.) $4.50

(D.) $4.60

​
Mathematics
2 answers:
Molodets [167]3 years ago
7 0

Answer:

I am assuming you meant to say '4' instead of '412'. In which case the answer is A.

Step-by-step explanation:

4 + 1 x .80 is 4.00 even. Good luck in your endeavors!

vodomira [7]3 years ago
3 0

412 pounds for him + 1 pound for his friend = 413 total pounds x $0.80 per pound = $330.40

Sorry, I don’t see this as an answer choice.

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Step-by-step explanation:

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PLEASE HELP ASAP. WILL GET BRAINEST
Montano1993 [528]
Part A - 226.865 or 226.87
Part B - 120
Part C - 106.865
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How to do the problem
marta [7]
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
8 \frac{1}{4}  + 9 \frac{1}{4}  + 8 \frac{7}{8}  + 9 \frac{5}{8}  + 10 \frac{3}{4}
=  \frac{8 \times 4 + 1}{4}  +  \frac{9 \times 4 + 1}{4}  \\  +  \frac{8 \times 8 + 7}{8}  +  \frac{9 \times 8 + 5}{8} \\  +  \frac{10 \times 4 + 3}{4}
=  \frac{33}{4}  +  \frac{37}{4}  +  \frac{71}{8}  +  \frac{77}{8}  +  \frac{43}{4}  \\  =  \frac{33 \times 2}{4 \times 2}  +  \frac{37 \times 2}{4 \times 2}  +  \frac{71}{8}  \\  +  \frac{77}{8}  +  \frac{43 \times 2}{4 \times 2}
=  \frac{66 + 74 + 71 + 77 + 86}{8}
=  \frac{374}{8}  =  \frac{186}{4}
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
\frac{186 - 153}{4}  =  \frac{33}{4}  = 8 \frac{1}{4}

The leftover watermelon is 8 & 1/4 pounds.
6 0
3 years ago
What is the equation of the line
serg [7]

Answer:

y=1/2x+2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Determine the solution set of (x - 4)2 = 12. {4 + 2√3, 4 - 2√3} {4 - 2√3, 4 - 2√3} {2√3 + 4, 2√3 - 4}
Alina [70]

Answer:

{4 + 2√3, 4 - 2√3} thus the solution is A.  x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)

Step-by-step explanation:

Solve for x over the real numbers:

(x - 4)^2 = 12

Take the square root of both sides:

x - 4 = 2 sqrt(3) or x - 4 = -2 sqrt(3)

Add 4 to both sides:

x = 4 + 2 sqrt(3) or x - 4 = -2 sqrt(3)

Add 4 to both sides:

Answer: x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)

4 0
3 years ago
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