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Basile [38]
3 years ago
12

Jellybeans cost $0.80 per pound. Howard buys 412 pounds of jellybeans for himself and 1 pound for his friend. What is the total

cost of the jellybeans Howard buys?
(A.) $4.00

(B.) $4.40

(C.) $4.50

(D.) $4.60

​
Mathematics
2 answers:
Molodets [167]3 years ago
7 0

Answer:

I am assuming you meant to say '4' instead of '412'. In which case the answer is A.

Step-by-step explanation:

4 + 1 x .80 is 4.00 even. Good luck in your endeavors!

vodomira [7]3 years ago
3 0

412 pounds for him + 1 pound for his friend = 413 total pounds x $0.80 per pound = $330.40

Sorry, I don’t see this as an answer choice.

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When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

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P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

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Answer:

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Step-by-step explanation:

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