Ask question

Ask question

All categories

2 years ago

13

Consider the complex number z = 27i. what are the characteristics of the cube roots of z? use the drop-down menus to complete ea

ch sentence. the cube roots are located on a circle with center at the pole and radius of . the cube roots have arguments which differ by π over 3.

1 answer:

wlad13 [49]2 years ago

4 0

The drop-down menu will be 3 and 2.

<h3>What is the complex number?</h3>

Real and imaginary numbers combine to form complex numbers with two components. Complex numbers serve as the foundation for more complex math, including algebra. They have various practical applications, particularly in electronics and electromagnetism.

The complex number z = 27i.

The radius of the cube root is: $r\sqrt[3]{x}$

$r\sqrt[3]{27}$

$r=3$

Cube roots are located in a circle with a center at the origin and a radius of 3 units.

The complex number,z=a+ib is; Θ = tan⁻¹(b/a)

The complex number z=0+27i is:

Θ = tan⁻¹(27/0)

Θ = π/2

Cube roots have more than 3 arguments that differ by 2 π.

Therefore, The drop-down menu will be 3 and 2.

To learn more about the complex number, refer to:

brainly.com/question/11089283

#SPJ4

You might be interested in

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago

Help... It's homework, I need ur Help :""""")

pochemuha

Answer:

112

Step-by-step explanation:

the formula for area is length times width,so in this case 14×8 = the area

6 0

3 years ago

A coin is tossed 8 times. Which of the following represents the probability of the coin landing on heads all 8 times?

ElenaW [278]

Answer:

$\large\boxed{\large\boxed{Probability=1/256\approx 0.0039}}$

Explanation:

Since, there are two possible outcomes for every toss (head or tail), the sample space for<em> a coin tossed 8 times</em> is 2×2×2×2×2×2×2×2 = 2⁸ = 256.

<em>Landing on heads all 8 times</em> is just one of the possible outcomes: HHHHHHHH ⇒ 1.

Hence, the <em>probability </em>is calculated from its own definition:

Probability = number of favorable outcomes / number of possible outcomes

$Probability=1/256\approx 0.0039\text{ }\leftarrow answer$

8 0

3 years ago

Need help only good answer plis!

Nesterboy [21]

A. The angles at the intersection of the two lines can be proven to be congruent and complementary . so they meet at a right angle and the lines are perpendicular.

<u>Step-by-step explanation:</u>

In above question, In order to find whether AB ⊥ CD, Using compass construction & rounder , keep the tip at A and cut arcs at line CD . Follow the same process again with tip at B and cut arcs at line CD . Do this both sides of Line CD i.e. on left side of AB & on right side of AB. Now, join the intersection points of both side arcs which are intersecting each other. Now, to prove both are right angle to each other i.e. AB ⊥ CD , can be done by proving congruent and complementary , so they meet at a right angle and Hence , the lines are perpendicular i.e. AB is inclined to CD at angle of 90°.

8 0

3 years ago

V^2=12^2+2(-6)(9) answer please i am waitind

il63 [147K]

Answer:

V = 6 or V = -6

Step-by-step explanation:

Solve for V over the real numbers:

V^2 = 12^2 - 6 2 9

12^2 + 2 (-6) 9 = 36:

V^2 = 36

Take the square root of both sides:

Answer: V = 6 or V = -6

3 0

3 years ago

Read 2 more answers