The answers are:
P(9, 2) = 72
P(5, 5) = 120
P(7, 7) = 5040
These are examples of permutations. The problems are asking us to find the total number of ways an event can happen.
In the first case, P(9, 2), we are asked to find the ways that 2 things can be chosen out of a group of 9.
9 x 8 = 72
P(5, 5) = 5 x 4 x 3 x 2 x 1
P(7, 7) = 7 x 6 x 5 x 4 x 3 x 2 x 1
Answer:
x = 13 smaller integer
x + 2 = 15 the other integer
Step-by-step explanation:
x = the smaller integer
x + 2 = the next integer
7(x) = 61 + 2(x + 2)
7x = 61 + 2x +4
5x = 61 + 4
5x = 65
x = 13 smaller integer
x + 2 = 15 the other integer
Answer:
If the second of the three numbers is
n
, then the first and third are
n- 1
and n
+
1
, so we find:
117
=
(
n
−
1
)
+
n
+
(
n
+
1
)
=
3n
Dividing both ends by
3 we find:
n
=
117/ 3
=
39
So the three numbers are:
38
,
39
,
40
Step-by-step explanation : I hope it helps please don't forget to mark me brainliest . :)
