Answer:
The 95% confidence interval for the proportion of American adults who smoked in 2008 is (20.1%, 21.1%).
Step-by-step explanation:
The critical value of <em>z</em> for 95% confidence level is:
<em>z</em> = 1.96
Compute the 95% confidence interval for the proportion of American adults who smoked in 2008 as follows:


Thus, the 95% confidence interval for the proportion of American adults who smoked in 2008 is (20.1%, 21.1%).
Both have slope 4 and intercept 3 so they are coincident lines
Combine the like terms
1.7m^2 + 2.5m^2 + 6.5n - 4n - n
4.2 m^2 + 1.5 n
Answer:
-6+3
Step-by-step explanation: