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3 years ago

The domain of a function is

Mathematics

2 answers:

Gre4nikov [31]3 years ago

3 0

Answer:

B.the set of all first elements of the function

Step-by-step explanation:

the domain is all the x variables in a function

Gekata [30.6K]3 years ago

3 0

Answer:

B. The set of all first elements of the function.

Step-by-step explanation:

We have been given a incomplete sentence. We are asked to complete our given sentence.

We know that the domain of a function is all real values of independent variable for which a function is defined and gives exactly one output.

We know that independent variable is x, which is first element of a point, therefore, the domain of a function is the set of all first elements of the function.

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Solve the simultaneous equations

Black_prince [1.1K]

Answer:

Step-by-step explanation:

4x + 3y = 24

4x - y = 8

4x + 3y = 24

-4x + y = -8

4y = 16

y = 4

4x - 4 = 8

4x = 12

x = 3

(3, 4)

8 0

2 years ago

Find all solutions of the equation in the interval [0,2pi).

Setler79 [48]

Csc theta=-2 then theta equals csc^-1(-2) then theta would equal 5pi/6, 7pi/6

3 0

3 years ago

Evaluate the expression 3x^2+4x^3 when x=4.

larisa [96]

Step-by-step explanation:

304

plug 4 in for x

3(4)^2 + 4(4)^3 = 304

48 + 256 = 304

6 0

3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

How to solve which fraction is larger 10/13 or 11/14 or 14/15 or 17/18

alexandr402 [8]

To solve these type of problem you have to make the denominator the same or use the claculator.

let us do this problem by making the denominator the same.

$\frac{10}{13} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{11}{14} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{14}{15} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{17}{18} \\\\ \frac{10}{13}\times \frac{3780}{3780} \ \ \ \ \ \ \ \ \ \frac{11}{14} \times \frac{3510}{3510} \ \ \ \ \ \ \ \ \ \frac{14}{15} \times \frac{3276}{3276} \ \ \ \ \ \ \ \ \ \frac{17}{18} \times \frac{2730}{2730}$

$\frac{37800}{49140} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{38610}{49140} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{45864}{49140} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{46410}{49140}$

So, now. the one with the largest numerator is the largest fraction

In this case, $\frac{46410}{49140}$ is the largest which is equal to $\frac{17}{18}$ .

So, the largest fraction is $\frac{17}{18}$ .

5 0

3 years ago