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NikAS [45]
3 years ago
11

The area of a rectangular television screen is 3456 in^2. The width of that screen is 24 inches longer than the length. What is

a quadratic equation the represents the area of the screen? What are the dimensions of the screen?
Mathematics
1 answer:
shutvik [7]3 years ago
4 0
1. The problem says that the television has a rectangular shape. So, the formula for caculate the area of a rectangle is:

 A=LxW

 "A" is the area of the rectangle (A=3456 inches²).
 "L" is the the length of the rectangle.
 "W" is the width of the rectangle.

 2. The <span>width of the screen is 24 inches longer than the length. This can be expressed as below:

 W=24+L

 3. Then, you must substitute </span>W=24+L into the formula A=LxW:
<span>
 </span>A=LxW
<span> 3456=L(24+L)
 3456=24L+L</span>²
<span>
 4. The quadratic equation is:

 L</span>²+24L-3456=0

 5. When you solve the quadratic equation, you obtain:

 L=48 inches

 6. Finally, you must substitute the value of the length, into W=24+L:

 W=24+L
 W=24+48
 W=72 inches

 7. Therefore, the dimensions of the screen are:

 L=48 inches
 W=72 inches<span> </span>
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