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antoniya [11.8K]

3 years ago

5

Five cards are labeled 1 to 5 face down on the table and then mixed up. What is the likelihood that I will draw an even-numbered

card?

2 answers:

marshall27 [118]3 years ago

7 0

It would be a 2/5 chance that youll pull and even card out.

Kaylis [27]3 years ago

4 0

First you do the even number up to five 1,2,3,4,5, the even numbers are 2 and 4
so you have a 2 out of five chance to get a even number.

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When two fractions are between 0 & 1 half how do you know which fraction is greater explaina

oksian1 [2.3K]

Example- 1/3 or 1/5, which is larger? If you divide 1 by 3 the answer is 0.33 If you divide 1 by 5 it's 0.2. Since 0.33(1/3) is larger that would be the answer.
sorry if I make this confusing.
basically divide the top by the bottom to see which is larger. Then compare the fractions.

5 0

3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

4 years ago

Select all pairs of numbers that have a least common multiple of 24.

Vlada [557]

3 and 8
6 and 8
8 and 12

5 0

3 years ago

Read 2 more answers

48=3 times 2 to the power of a 56=7 times 2 to the power of bWhat are the values of a and b?a= b=

Digiron [165]

9514 1404 393

Answer:

a = 4
b = 3

Step-by-step explanation:

From your knowledge of multiplication tables, you know ...

48 = 6·8 = 3·2·2·2·2 = 3·2^4 . . . . a = 4

56 = 7·8 = 7·2·2·2 = 7·2^3 . . . . . . b = 3

8 0

2 years ago

4000 + 12 343 x 2 =(A)

Vikentia [17]

Answer:

12,686

Step-by-step explanation:

add both numbers up then multiply by 2

7 0

3 years ago