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Gekata [30.6K]
4 years ago
8

Which figure has two pairs of congruent sides and more than two lines of symmetry?

Mathematics
2 answers:
Advocard [28]4 years ago
5 0
C. trapezoid

a trapezoid's legs are congruent, while the bases are symmetrical

a square is the answer you would want, because it is always true, while a trapezoid is only "sometimes" true

thanks Kaikers :D


san4es73 [151]4 years ago
5 0
The correct answer is "B" square. A square has 4 equal sides (and angles), so it is the only polygon that has more than 2 lines of symmetry. 

I hope this helps!
~kaikers
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Select the correct answer.
Crazy boy [7]

check the picture below.

now, if we split that triangle like so with that red line, we can use the right-triangle there, to get θ.


\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{3}}\implies tan(\theta )=1\implies tan^{-1}(\theta )=tan^{-1}(1)\implies \measuredangle \theta =\cfrac{\pi }{4}

8 0
3 years ago
Simplify (2^3)^–2.<br> A: -1/64<br> B: 1/64<br> C: 2<br> D: 64
lions [1.4K]

Answer:

B: 1/64

Step-by-step explanation:

2^3 = 8

8^(-2)=1/(8^2)=1/64

5 0
3 years ago
Whats the slope when the independent variable increase while the dependent variable increases?
ira [324]
When both increase, the slope is positive (+)/(+)=(+)
8 0
3 years ago
PLZ HELP! VERY URGENT!<br> A line passes through (6,3), (8,4), and (n,-2). Find the value of n.
Phantasy [73]

We have a line passing through 3 points. We can use the first
two points to find the equation of the line.
(6,3), (8,4)

slope m = (4-3)/(8-6) = 1/2

We can use the point slope form y-y1 = m(x-x1) or
the slope intercept form y = mx + b
to find the equation of the line.

Let's take the point (6,3) and use y = mx + b to find b
y = 3, x = 6, m = 1/2

3 = (1/2)(6) + b
3 = 3 + b
0 = b

The equation of our line is y = (1/2)x

We have a line of equation y = (1/2)x going through point (n,-2)

Plugging in we have: -2 = (1/2)n
2(-2) = n
-4 = n

Your answer is n = -4

NOTE: looking at the 3 points as given initially: (6,3), (8,4), (n,-2)
We can see that 3 = (1/2)6 and 4 = (1/2)8 so -2 = (1/2)n makes sense

Hope this helps you :)
5 0
4 years ago
Read 2 more answers
Help me solve this please
damaskus [11]

1) A quadratic will have no real roots when its discriminant is negative


0 = ax^2 + bx + c = x^2 + 2k x + (4k-3)


d = b^2 - 4ac =  (2k)^2 - 4(1)(4k-3) = 4k^2 - 16k + 12 < 0


Dividing by 4,


k^2 - 4 k + 3 < 0 \quad\checkmark


We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.


(k-3)(k-1)


That's true for


1 < k < 3


2) We look for the meet of the line and the parabola:


2x + k + 2 = 2x^2 + (k+2)x + 8


0 = 2x^2 + kx + (6-k)


For two intersections we need a positive discriminant:


k^2 - 4(6-k)(2) > 0


k^2 + 8k - 48 > 0


(k+12)(k-4) > 0


That's means two negative or two positive, so


k < 12 or k > 4


6 0
3 years ago
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