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ad-work [718]
3 years ago
5

How does the structure of a substance and the energy of its particles relate to its properties in different states of matter?

Chemistry
1 answer:
Alexus [3.1K]3 years ago
3 0

Explanation: For solid or cold objects, (like ice), the particles are close together and not moving. For liquids, (like water), the particles are moving freely and limited energy depending on if it is warm or not. For gas, the particles are way spread out, and moving fast.

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A sample of oxygen gas occupies a volume of 229.5 mL at 762.7 torr pressure. What volume in mL will it occupy at 704.5 torr pres
Fed [463]

Answer:

248.4 mL

Explanation:

In order to answer this problem we can use <em>Boyle's law</em>, which states that at a constant composition:

  • P₁V₁ = P₂V₂

Where in this case:

  • P₁ = 762.7 torr
  • V₁ = 229.5 mL
  • P₂ = 704.5 torr
  • V₂ = ?

We <u>input the data</u>:

  • 762.7 torr * 229.5 mL = 704.5 torr * V₂

And <u>solve for V₂</u>:

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3 years ago
Nuclear decay is a first-order kinetics process. What is the half-life of a radioactive isotope if it takes 233 minutes for the
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<u>Answer:</u> The half life of the given radioactive isotope is 43.86 minutes

<u>Explanation:</u>

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = ?

t = time taken for decay process = 233 minutes

[A_o] = initial amount of the reactant = 0.500 M

[A] = amount left after decay process =  0.0125 M

Putting values in above equation, we get:

k=\frac{2.303}{233}\log\frac{0.500}{0.0125}\\\\k=0.0158min^{-1}

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half-life of the reaction = ?

k = rate constant = 0.0158min^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.0158min^{-1}}=43.86min

Hence, the half life of the given radioactive isotope is 43.86 minutes

8 0
3 years ago
Unit 2 Test
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The answer is community
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What is the titration​
Inga [223]
Titration is the slow edition of one solution of unknown concentration to a noun volume up another solution of unknown concentration until the reaction reaches neutralization which is often indicated by a color change
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Doss [256]

Answer:

YASSSSSSS

Explanation:

i think the answer is true

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3 years ago
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