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Nikolay [14]
3 years ago
6

How do you factor b^2-81

Mathematics
1 answer:
Naddik [55]3 years ago
7 0
The middle number is 0 and the last is -81Factoring means we want something like(b+_)(b+_)We need two numbers that add together to get and Multiply to get -81which are 9 and -9:<span><span>9+-9 = 0 and </span><span>9*-9 = -81</span></span>
Fill in the blanks in
(b+_)(b+_)
with 9 and -9 to get...<span><span>(<span>b+9</span>)</span><span>(<span>b−9</span>)</span></span>
The answer is : (b+9)(b−9)
<span>
</span>
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Answer:

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Step-by-step explanation:

Given

Geometry Progression

T_1 = 500

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Required

Calculate the second term

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T_n = ar^{n-1}

For first term: Tn = 500 and n = 1

500 = ar^{1-1}

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32 = ar^{4-1}

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Substitute 500 for a

32 = 500 * r^3

Make r^3 the subject

r^3 = \frac{32}{500}

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Using:  T_n = ar^{n-1}

n = 2     r = 0.4     and a = 500

T_{2} = 500 * 0.4^{2-1}

T_{2} = 500 * 0.4^1

T_{2} = 500 * 0.4

T_{2} = 200

<em>Hence, the second term is 200</em>

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