Answer:
A. LCM of 6,9, and 15 is 90.
B. LCM of 3,12, and 16 is 48.
C. LCM of 8,9, and 12 is 72.
D. LCM of 24 and 18 is 72.
E. LCM of 21 and 28 is 84.
F. LCM of 19 and 42 is 798.
Step-by-step explanation:
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Answer: B. g(x)=3x-2-7
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Anything multiplied by 0 =0
So what is left is 90x100x12x13x34 which is=47,736,000
Answer: 0.0035
Step-by-step explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e. and
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .
Hi yes I can:)
Its the first option. 3 1/2