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victus00 [196]
3 years ago
7

An empty shipping box box weighs 250 grams. The box is filled with T shirts weighs 132.5 grams. The equation W=250+132.5T repres

ent the relation ship between the quantities not the solution, where W is the weighs in grams of the filled box T is the number of shirts in the box. ​. WHAT DOES THE SOLUTION T=8, W=1310 MEAN IN THIS SOLUTION
Mathematics
1 answer:
garik1379 [7]3 years ago
7 0

Answer:

the solution means you can solve for either of the variables when one of the variables is known

Step-by-step explanation:

Given:

W=250+132.5T

Where,

W = weights in grams of the filled box

T = number of shirts in the box

T=8 when W=1310

W=250+132.5T

Substitute T = 8 into the equation

W = 250 + 132.5(8)

= 250 + 1,060

= 1,310

The solution means when number of shirts in the box is 8, the total weight in grams of the filled box is 1,310

It also means you can solve for the number of shirts if weight of the box is given as 1310

W=250+132.5T

1310 = 250 + 132.5T

1310-250 = 132.5T

1,060 = 132.5T

T = 1,060 / 132.5

= 8

T = 8

Therefore, the solution means you can solve for either of the variables when one of the variables is known

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An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. ​(a) Use a bin
Advocard [28]

Answer:

a) 0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

b) 0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

Step-by-step explanation:

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

To use the Poisson approximation for the binomial, we have that:

\mu = np

1 in every 2500 automobiles produced has a particular manufacturing defect.

This means that p = \frac{1}{2500} = 0.0004

a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of 7000 cars.

This is P(X = 4) when n = 7000. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{7000,4}.(0.0004)^{4}.(0.9996)^{6996} = 0.1558

0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

(b) The Poisson distribution can be used to approximate the binomial distribution for large values of n and small values of p.

Using the approximation:

\mu = np = 7000*0.0004 = 2.8. So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-2.8}*(2.8)^{4}}{(4)!} = 0.1557

0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

6 0
3 years ago
Increasing on the intervals<br><br> Decreasing on the intervals
tatyana61 [14]

The increasing and decreasing intervals are marked on the graph and attached below.

The red arrow mark shows the part where graph is decreasing

The green arrow mark shows the part where graph is increasing

There is no end point or starting point for the graph

The graph starts decreasing at -∞  and it decreases till it reaches -2.5

Also the graph start decreasing at 0 and goes to +∞

So we have two decreasing intervals

(-∞ , -2.5) U (0, ∞)

The graph starts increasing at -2.5  and it increases till it reaches 0

So increasing interval is

(-2.5, 0)

6 0
3 years ago
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