All categories

2 years ago

San R APOR is a right triangle. IF RO = 8, what is PO? mios 16

Mathematics

1 answer:

attashe74 [19]2 years ago

6 0

Answer:

PQ = 16

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos60° = $\frac{1}{2}$ , then

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{RQ}{PQ}$ = $\frac{8}{PQ}$ = $\frac{1}{2}$ ( cross- multiply )

PQ = 8 × 2 = 16

You might be interested in

The nth term of a sequence is 2N - six

dolphi86 [110]

Answer:

ok nice to know

Step-by-step explanation:

that wasnt even a ????

4 0

2 years ago

Which set of ordered pairs represents a function?

Georgia [21]

Answer:

the second one

Step-by-step explanation:

in order for it to be a function the x values CANNOT repeat.

in answer a the x value -6 repeats so that cannot be a function

in answer b none of the x values repeat so its probably this one but lets check the other ones just in case

in answer c the x value 8 repeats so it cannot be this one

in answer d the x value -2 repeats so it cant be this one \

b is the only one that does have repeating x values therefore it is the second one

6 0

2 years ago

Read 2 more answers

A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3>Given :-</h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

We have to find the distance between the golf ball and the center of the green .

<h3>Let's Begin :-</h3>

Let assume that the distance between the golf ball and central of green is x

Here, 

Distance between marker and centre of green is 150 yards
That is, Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
That is, Angle = 100°
The golfer peces off 30 yards to his ball
That is, Base = 30 yards

According to the law of cosine :-

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

So, For Hypotenuse law of cosine will be :-

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

Subsitute the required values,

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

Jenna, Tatiana, and Nina have decided to share their Halloween candy.

Shtirlitz [24]

Idkgccghhhbbjjfxgvbijv

7 0

3 years ago

One of two supplementary angles is 8° more than one-third of the other angle. Find the measure of each of the angles.

storchak [24]

Hello,

Let's a and b the 2 angles.

a+b=180 (1)
a=b/3+8 ==> 3a-b=24 (2)

(1)+(2)==>4a=204==>a=51(°) and b=180-51=129(°)

Proof:
129/3+8=43+8=51
129+51=180

6 0

2 years ago