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RUDIKE [14]
2 years ago
10

Writing in math use counters.tell how to make 10 when adding 8 5

Mathematics
2 answers:
vesna_86 [32]2 years ago
7 0

Answer: Counters are an excellent method that children can use in their attempts to master math skills including counting, adding, subtracting, making patterns and comparing numbers.


The given sum = 8+5

To make 10 for adding them, first check which number is nearest to the 10.

We can see the number is 8 which is nearest to 10 in the given sum.

Now, to make a 10 here, we need to add 2 to 8 , and  we subtract 2 from 5 such that the sum would become

8+5\\=8+2+(5-2)\\=10+3\\=13


kaheart [24]2 years ago
5 0
<span>How can you make 10 when adding 8 + 5?
Well, let’s try:
Adding 8 and 5 is equals to 13
=> 8+5=13 (How can you get 10)
Well 13 has 2 digits where 3 is placed in ones and 1 is place in tens. Therefore adding 8 and 5 will result to 10.

</span>



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The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
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{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

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AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

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Step-by-step explanation:

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Step-by-step explanation:

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-129 = -48 - n <br> Thank you
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Divide both sides by -1.

−n/−1  =  −81/−1

n=81


3 0
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