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Veseljchak [2.6K]
3 years ago
10

What is the value of 6X + 7 y - 5 when x equals two and Y equals 3​

Mathematics
2 answers:
il63 [147K]3 years ago
5 0

Answer:

28

Step-by-step explanation:

6x + 7y - 5

x = 2

y= 3

6(2) + 7(3) - 5

12 + 21 - 5

33 - 5

28

Hope this helps! Have a wonderful day.

tankabanditka [31]3 years ago
3 0

Answer:

<h2>28</h2>

Step-by-step explanation:

6x + 7y - 5

Substitute x = 2, y = 3

(6)(2) + (7)(3) - 5              <em>first multiplication</em>

= 12 + 21 - 5

= 33 - 5

= 28

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Demonstrate two different ways to solve the equation 5^(2x+1) = 25.
Tanzania [10]

Answer:

Step-by-step explanation:

Method 1: Taking the log of both sides...

So take the log of both sides...

5^(2x + 1) = 25

log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...

(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...

(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...

(2x)log 5 + log 5 - log 5 = log 25 - log 5

(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)

(2x)log 5 = log 5 <-- divide both sides by log 5

(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..

2x = 1

x=1/2

Method 2

5^(2x+1)=5^2

2x+1=2

2x=1

x=1/2

3 0
3 years ago
If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
Brrunno [24]

Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}.

The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

The area (in square inches) of a circle of radius 10 inches is:

\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

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A if you multiply the divide the. Subtract the add the. Iudjnff
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Which statements describe America’s workforce during World War II? Check all that apply.
soldier1979 [14.2K]

Step-by-step explanation:

hundreds of thousands of women signed up for the US military

5 0
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Read 2 more answers
Evaluate t-u/v when t=2 u=(-8) v(-1/2)
Dovator [93]
Simple, plug n chug...

t- \frac{u}{v}

t=2

u=-8

v=-0.5

Now, plug in what you have,

2- \frac{-8}{-0.5}

\frac{-8}{-0.5} =16

Now,

2-16=-14

Thus, your answer, -14.
5 0
2 years ago
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