Answer:
-3
Step-by-step explanation:
Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by
where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:
and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:
Answer:
the domain is equal to all real numbers greater than or equal to 0
Step-by-step explanation:
The domain is all the numbers in which the graph reaches in regards to the x axis
We can see from the graph that it starts at 0 and then moves right
THis means that the domain is equal to all real numbers greater than or equal to 0
Answer:
x = ln 10
Step-by-step explanation:
You meant e^x - 1 = 9. Let's isolate e^x, by adding 1 to both sides. We get:
e^x = 10
Now make use of the property ln a = b <=> a = e^b
Then e^x = 10 becomes
x = ln 10
Answer:
It can't be simplified
Step-by-step explanation: