R 2x-6+3=6x-5 please help
2 answers:
Ok so if this is basic algebra it should be x=-1
First combine like terms:
you can add 6 and 3 in 2x-6+3
2x-9=6x-5
Second get x alone:
you can add 9 to both sides and get
2x=6x+4
then you can subtract 6 from both sides which would leave you
-4x=4
finally divide -4 from both sides and you get
x=-1
I hope this helps! Have a nice day or night :)
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


Add sides 5


Subtract sides 2x


Divide sides by 4


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CHECK :



Thus the solution is correct....
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